SQL: Employees Earning More Than Their Manager (Self Join)

> This problem is paper-only - see explanation for the canonical SQL solution. (LeetCode classic 181.) Given: ``` Employee(id, name, salary, manager_id) -- manager_id is nullable, FKs Employee.id ``` Return the names of employees whose salary is **strictly greater than** their direct manager's salary. Order alphabetically. **For the auto-grader:** implement `employeesEarningMoreThanManager(employees)`.